TestHub
TestHub

Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorForce & Energy analysisMedium2 minPYQ_2021
PhysicsMediumnumerical

A parallel plate capacitor whose capacitance C is 14 pF is charged by a battery to a potential difference V=12 V between its plates. The charging battery is now disconnected and a porcelain plate with k=7 is inserted between the plates, then the plate would oscillate back and forth between the plates with a constant mechanical energy of _______ pJ.

(Assume no friction)

Answer:
864.00
Solution:

Ui=12×14×12×12 pJ  U=12CV2

=1008 pJ

Uf=10087pJ=144 pJ  Cm=kC0

Mechanical energy=ΔU

=1008-144

=864 pJ

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis
2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...