Start Free Mock LoginAlready registered? Login here

Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorBasic capacitor analysis with dielectricMedium2 minPYQ_2021

PhysicsMediumsingle choice

Two identical parallel plate air capacitors are connected in series to a battery of emf ' $V$ '. If one of the capacitor is inserted in liquid of dielectric constant ' $K$ ' then, potential difference of the other capacitor will become

Options:

Answer:

Solution:

Let the capacitance of capacitors are C initially. So, afterward $C_{1} = KC$ and $C_{2} = C$ p.d. across capacitor $C_{2}$ is $V_{2} = \frac{C _{1} V}{C _{1} + C _{2}} = \frac{KCV}{C + KC} = \frac{KV}{K + 1}$

Stream:MHT_CETSubject:PhysicsTopic:CapacitorSubtopic:Basic capacitor analysis with dielectric

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...