A parallel plate capacitor with air between the plates has a capacitance of 8 pF . Calculate the capacitance if the distance between the plates is reduced by half and the space between them is filled

Question

A parallel plate capacitor with air between the plates has a capacitance of 8 pF . Calculate the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant. (k =6)

TestHub · Accepted Answer

Capacity of parallel plate capacitor C = d k ε 0 ​ A ​ ( For air k r ​ = 1 ) So, d ε 0 ​ A ​ = 8 × 1 0 − 12 If d → 2 d ​ and k r ​ → 6 then new capacitance C ′ = 6 × d /2 ε 0 ​ A ​ = 12 d ε 0 ​ A ​ = 12 × 8 pF = 96 pF

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