Start Free Mock LoginAlready registered? Login here

Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorCircuit AnalysisEasy2 minPYQ_2020

PhysicsEasysingle choice

Three condensers of capacities $C_{1}, C_{2}, C_{3}$ are connected in series with a source of e.m.f. $V$ . The potentials across the three condensers are in the ratio of

Options:

Answer:

Solution:

When capacitors are connected in series, the charge is the same on all the capacitors. $Q = C_{1} V_{1} = C_{2} V_{2} = C_{7} V_{3} Or \frac{V _{1}}{\frac{1}{C _{1}}} = \frac{V _{2}}{\frac{1}{C _{2}}} = \frac{V _{3}}{\frac{1}{C _{3}}}$

Stream:MHT_CETSubject:PhysicsTopic:CapacitorSubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...