Physics - Capacitor Question with Solution | TestHub

Given, resultant capacity, ${\mathrm{C}}_{\mathrm{eq}}=2\mu \mathrm{F}$ The equivalent capacity of the circuit is given by $\frac{1}{C_{aq}}=\frac{1}{C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}\dots (\because$ all capacitors are in series) $\begin{array}{l}\frac{1}{C_{eq}}=\frac{5}{C}\\ \frac{1}{2\mu F}=\frac{5}{C}\\ \Rightarrow C=10\mu F\end{array}$