Physics - Capacitor Question with Solution | TestHub

$\because$ Capacitance of a parallel plate capacitor, $\begin{array}{rl}\mathrm{C}& =\frac{{\epsilon }_0\mathrm{A}}{\mathrm{d}}\mathrm{A}=\frac{\mathrm{Cd}}{{\epsilon }_0}=\frac{2\times 0.5\times 10^{-2}}{8.85\times 10^{-12}}\\ & =1.130\times 10^9{\mathrm{m}}^2=1130{\mathrm{km}}^2\end{array}$