Physics - Capacitor Question with Solution | TestHub

Charge resides on the outer surface of a conducting hollow sphere of radius $\mathrm{R}$. We consider a spherical surface of radius $r<R$. By Gauss theorem
$$\begin{array}{l}{\int }_{\mathrm{s}}\overrightarrow{\mathrm{E}}\cdot \mathrm{ds}=\frac{1}{{\epsilon }_0}\times \mathrm{ch}arg\mathrm{e}\text{ enclosed or }\\ \mathrm{E}\times 4\pi {\mathrm{r}}^2=\frac{1}{{\epsilon }_0}\times 0\Rightarrow \mathrm{E}=0\end{array}$$ i.e electric field inside a hollow sphere is zero.