The amount of work done in increasing the voltage across the plates of the capacitor from 5 V to 10 V is W . The work done in increasing it from 10 V to 15 V will be

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The work done in increasing the potential is given by
$W = d U \propto (V_{2}^{2} - V_{1}^{2})$
$∴ \frac{W_{1}}{W_{2}} = \frac{(V_{2}^{2} - V_{1}^{2})}{{(V}_{3}^{2} - V_{2}^{2})} h e r e V_{1} = 5 v, V_{2} = 10 V a n d V_{3} = 15 V$
$∴ \frac{W}{W_{2}} + (\frac{100 - 25}{225 - 100}) = \frac{75}{125}$
$∴ W_{2} = 1.67 W$

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