Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorCircuit AnalysisMedium2 minPYQ_2014

PhysicsMediumsingle choice

During charging a capacitor, variations of potential $V$ of the capacitor with time $t$ is shown as

Answer:

Solution:

For charging the capacitor, $q = q_{0}$ $(1 - e^{\frac{- t}{CR}})$ And, Potential difference $V = V_{0} (1 - e^{- t / CR})$

Stream:VITEEESubject:PhysicsTopic:CapacitorSubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2014

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