Physics - Capacitor Question with Solution | TestHub

electric field in the dielectric-filled region is higher than that in the air-filled region

on the two halves of the bottom plate the charge densities are unequal

charge on the half of the top plate above the air-filled part is $\frac{Q}{K+1}$

capacitance of the capacitor shown above is $(1+K)\frac{C_0}{2},$ where $C_0$ is the capacitance of the same capacitor with the dielectric removed.