Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorForce & Energy analysisMedium2 minPYQ_2013

PhysicsMediumsingle choice

Two identical capacitors, have the same capacitance $C$ . One of them is charged to potential $V_{1}$ and the other to $V_{2}$ . The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is -

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Answer:

Solution:

Initial energy of combined system $U_{1} = \frac{1}{2} CV_{1}^{2} + \frac{1}{2} CV_{2}^{2}$ Final common potential, $V = \frac{V _{1} + V _{2}}{2},$ Final energy of system, $U_{2} = 2 \times \frac{1}{2} C (\frac{V _{1} + V _{2}}{2})^{2}$ Hence loss of energy $= U_{1} - U_{2}$ $= \frac{1}{4} C (V_{1} - V_{2})^{2}$

Stream:BITSATSubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: PYQ_2013

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