Physics - Capacitor Question with Solution | TestHub

$$\begin{array}{rl}\tau & =CR\\ {\tau }_1& =\left(C_1+C_2\right)\left(R_1+R_2\right)=18\mu \mathrm{s}\\ {\tau }_2& =\left(\frac{C_1{C}_2}{C_1+C_2}\right)\left(\frac{R_1{R}_2}{R_1+R_2}\right)=\frac{8}{6}\times \frac{2}{3}=\frac{8}{9}\mu \mathrm{s}\\ {\tau }_2& =\left(C_1+C_2\right)\left(\frac{R_1{R}_2}{R_1+R_2}\right)=(6)\left(\frac{2}{3}\right)=4\mu \mathrm{s}\end{array}$$