Physics - Capacitor Question with Solution | TestHub

$\mathrm{V}=300\mathrm{V},{\mathrm{C}}_1=2.0\mu \mathrm{F},{\mathrm{C}}_2=8.0\mu \mathrm{F}$, Net capacitance, $\frac{1}{{\mathrm{C}}_{\mathrm{s}}}=\frac{1}{{\mathrm{C}}_1}+\frac{1}{{\mathrm{C}}_2}$ $$\begin{array}{l}\Rightarrow {\mathrm{C}}_{\mathrm{s}}=\frac{{\mathrm{C}}_1{\mathrm{C}}_2}{{\mathrm{C}}_1+{\mathrm{C}}_2}\\ \Rightarrow {\mathrm{C}}_{\mathrm{s}}=\frac{2\times 8}{2+8}=\frac{16}{10}=1.6\mu \mathrm{F}\end{array}$$ Now total charge, $\mathrm{Q}={\mathrm{V}}_{\mathrm{s}}\times {\mathrm{C}}_{\mathrm{s}}=300\times 1.6\times 10^{-6}=4.8\times 10^{-4}\mathrm{C}$ $\because$ In series charge is same on capacitors $\Rightarrow$ Charge on $2\mu \mathrm{F}$ capacitor is $4.8\times 10^{-4}\mathrm{C}$