Physics - Capacitor Question with Solution | TestHub

In series combination of capacitors, charges on both capacitors will be same. $\begin{array}{l}{V}_s=\frac{Q}{C_1}+\frac{Q}{C_2}\\ \Rightarrow 1000=Q\left(\frac{1}{C_1}+\frac{1}{C_2}\right)\\ \Rightarrow 1000=Q\left(\frac{C_1+C_2}{C_1{C}_2}\right)\\ \Rightarrow Q=\frac{1000\times C_1{C}_2}{C_1+C_2}\\ Q=1000\times \frac{3\times 10^{-12}\times 6\times 10^{-12}}{(3+6)\times 10^{-12}}=\frac{18}{9}\times 10^{-9}\\ =2\times 10^{-9}\mathrm{C}\end{array}$