Physics - Capacitor Question with Solution | TestHub

In steady state the capacitors act as open circuits; current flows through the two resistive branches (2 Ω + 3 Ω and 3 Ω + 2 Ω) in parallel between the side rails.

Equivalent resistance: $R=(5\Vert 5)+0.5=3\Omega$, so total current = 2 A and the voltage between the rails is 5 V.

Each branch carries 1 A. Midpoint potentials (right rail as 0): top branch midpoint = 5 − 1×2 = 3 V; middle branch midpoint = 5 − 1×3 = 2 V.

The 1 μF capacitor joins the two branches at the left rail — both its plates sit at the same node, so it is shorted: q₁ = 0 → (A) is wrong.

The 3 μF capacitor similarly joins the branches at the right rail, so it is also shorted: q₃ = 0 → (C) is correct.

The 2 μF capacitor connects the two midpoints: $V_{2\mu F}=3-2=1\mathrm{V}$, so $q_2=2\mu F\times 1V=2\mu C$ → (B) is correct and (D) is wrong.

Hence (B) and (C).