A parallelogram is constructed on 5 a + 2 b and a − 3 b , ∣ a ∣ = 2 2 , ∣ b ∣ = 3 , a ^ ⋅ b ^ = 2 1 , then length of smaller diagonal is

Length of diagonals = ∣ ( 5 a + 2 b ) + ( a − 3 b ) ∣ and ∣ ( 5 a + 2 b ) − ( a − 3 b ) ∣

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MathematicsVectorMiscellaneous/MixedEasy2 min

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A parallelogram is constructed on $5 a + 2 b$ and $a - 3 b, ∣ a ∣ = 22, ∣ b ∣ = 3, \overset{a}{^} \cdot \hat{b} = \frac{1}{2}$ , then length of smaller diagonal is

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Solution:

Length of diagonals $= ∣ (5 \overline{a} + 2 \overline{b}) + (\overline{a} - 3 \overline{b}) ∣$ and $∣ (5 \overline{a} + 2 \overline{b}) - (\overline{a} - 3 \overline{b}) ∣$

Stream:JEESubject:MathematicsTopic:VectorSubtopic:Miscellaneous/Mixed

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