Let A BC D be a tetrahedron such that the edges AB , AC and AD are mutually perpendicular. Let the areas of the triangles ABC , ACD and ADB be 5,6 and 7 square units respectively. Then the area (in sq

Question

Let A BC D be a tetrahedron such that the edges AB , AC and AD are mutually perpendicular. Let the areas of the triangles ABC , ACD and ADB be 5,6 and 7 square units respectively. Then the area (in square units) of the △ BCD is equal to :

TestHub · Accepted Answer

Ar ( △ BC D ) = ( Ar ( △ ABC ) ) 2 + ( Ar ( ACD ) ) 2 + ( Ar ( △ ADB ) ) 2 ​ = 5 2 + 6 2 + 7 2 ​ = 110 ​

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