Mathematics - Vector Question with Solution | TestHub

MathematicsVectorReflection in a PlaneHard2 minQB

MathematicsHardsingle choice

Passage / Comprehension

Consider the plane $P:x+y+z=3$ and the circle $x^2+y^2=1, z=0$.

Image of the points on the circle in the plane P lies on

Answer:

Solution:

Reflecting $(cos θ, sin θ, 0)$ in $x + y + z = 3$ and eliminating $θ$ gives the plane $2 x + 2 y - z = 6$ .

Stream:JEESubject:MathematicsTopic:VectorSubtopic:Reflection in a Plane

⏱ 2mℹ️ Source: QB

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