Mathematics - Vector Question with Solution | TestHub

A plane passes point$\mathrm{P}(0,1,-1)$ and contains a line$\mathrm{L}:\frac{\mathrm{x}-1}{2}=\frac{\mathrm{y}-1}{3}=\frac{\mathrm{z}+2}{1}$. If R is a point on line$L$ such that$△PQR$ is right angled at$P$, where$Q(1,1,-2)$, then the value of$\frac{P{R}^2}{5}$ is$\mathrm{P}(0,1,-1)$$\mathrm{L}:\frac{\mathrm{x}-1}{2}=\frac{\mathrm{y}-1}{3}=\frac{\mathrm{z}+2}{1}$$\mathrm{Q}(1,1,-2)$$\frac{{\mathrm{PR}}^2}{5}$