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MathematicsVectorDot Product & Its Application ( Projection etc.)Easy2 minPYQ_2018
MathematicsEasynumerical

Consider the cube in the first octant with sidesOP, OQand OR of length1, along the x-axis, y-axis and z-axis, respectively, whereO(0,0,0)is the origin. LetS12,12,12be the centre of the cube andTbe the vertex of the cube opposite to the originOsuch thatSlies on the diagonalOT. Ifp=SP, q=SQ, r=SRandt=ST, then the value ofp×q×r×tis ______.

Question diagram: Consider the cube in the first octant with sides O P , O Q a
Answer:
0.50
Solution:


p=SP=12,-12,-12=12i^-j^-k^
q=SQ=-12,12,-12=12-i^+j^-k^
r=SR=-12,-12,12=12-i^-j^+k^
t=ST=12,12,12=12i^+j^+k^
p×q×r×t=14i^j^k^1-1-1-11-1×14i^j^k^-1-11111
=1162i^+2j^×-2i^+2j^=k^2=12

Stream:JEE_ADVSubject:MathematicsTopic:VectorSubtopic:Dot Product & Its Application ( Projection etc.)
2mℹ️ Source: PYQ_2018

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