If the lines 2 x + 1 = 1 y − 1 = 3 z + 1 and 2 x + 2 = 3 y − k = 4 z are coplanar, then the value of k is :

Two given planes are coplanar, if ⇒ ⇒ ⇒ − 2 − ( − 1 ) 2 2 k − 1 1 3 0 − ( − 1 ) 3 4 = 0 − 1 2 2 k − 1 1 3 1 3 4 = 0 ( − 1 ) ( 4 − 9 ) − ( k − 1 ) ( 8 − 6 ) + 6 − 2 = 0 k = 2 11

Mathematics - Vector Question with Solution | TestHub

MathematicsVectorVector equation of a line, Vector equation of the angle bisectorsMedium2 minPYQ_2013

MathematicsMediumsingle choice

If the lines $\frac{x + 1}{2} = \frac{y - 1}{1} = \frac{z + 1}{3}$ and $\frac{x + 2}{2} = \frac{y - k}{3} = \frac{z}{4}$ are coplanar, then the value of $k$ is :

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Answer:

Solution:

Two given planes are coplanar, if $\Rightarrow \Rightarrow \Rightarrow - 2 - (- 1) 22 k - 1 13 0 - (- 1) 34 = 0 - 1 22 k - 1 13 134 = 0 (- 1) (4 - 9) - (k - 1) (8 - 6) + 6 - 2 = 0 k = \frac{11}{2}$

Stream:JEESubject:MathematicsTopic:VectorSubtopic:Vector equation of a line, Vector equation of the angle bisectors

⏱ 2mℹ️ Source: PYQ_2013

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