cos 2 ( 6 π + θ ) − sin 2 ( 6 π − θ ) =

cos 2 ( 6 π + θ ) − sin 2 ( 6 π − θ ) = cos ( 6 π + θ + 6 π − θ ) cos ( 6 π + θ − 6 π + θ ) = cos 6 2 π cos 2 θ = 2 1 cos 2 θ

Mathematics - Trigonometric Ratios & Identities Question with Solution | TestHub

MathematicsTrigonometric Ratios & IdentitiesAddition, Multiplication, Subtraction formula based,Multiple/Submultiple anglesEasy2 minPYQ_2014

MathematicsEasysingle choice

$cos^{2} (\frac{π}{6} + θ) - sin^{2} (\frac{π}{6} - θ) =$

Options:

Answer:

Solution:

$cos^{2} (\frac{π}{6} + θ) - sin^{2} (\frac{π}{6} - θ) = cos (\frac{π}{6} + θ + \frac{π}{6} - θ) cos (\frac{π}{6} + θ - \frac{π}{6} + θ) = cos \frac{2 π}{6} cos 2 θ = \frac{1}{2} cos 2 θ$

Stream:BITSATSubject:MathematicsTopic:Trigonometric Ratios & IdentitiesSubtopic:Addition, Multiplication, Subtraction formula based,Multiple/Submultiple angles

⏱ 2mℹ️ Source: PYQ_2014

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