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Mathematics - Trigonometric Ratios & Identities Question with Solution | TestHub

MathematicsTrigonometric Ratios & IdentitiesBasic Identities & T RatiosEasy2 minPYQ_2002

MathematicsEasysingle choice

The period of $sin^{2} θ$ is

Options:

Answer:

B

Solution:

$sin^{2} θ = \frac{1 - c o s 2 θ}{2};$ Period $= \frac{2 π}{2} = π$

Stream:JEESubject:MathematicsTopic:Trigonometric Ratios & IdentitiesSubtopic:Basic Identities & T Ratios

⏱ 2mℹ️ Source: PYQ_2002

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