The number of solutions of the equation sin 2 π ( 1 − x ) + cos 2 π ( 1 − x ) = ∣ lo g e ∣ x ∣ 3 + 1 ∣ is /are

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MathematicsTrigonometric EquationTrigonometric EquationHard2 minQB

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The number of solutions of the equation $sin \frac{π}{2} (1 - x) + cos \frac{π}{2} (1 - x) = ∣ lo g_{e} ∣ x ∣^{3} + 1 ∣$ is /are

Answer:

Solution:

Simplify, $sin π x = (lo g ∣ x ∣)^{3}$ By graph,

we get 6 solutions.

Stream:JEESubject:MathematicsTopic:Trigonometric EquationSubtopic:Trigonometric Equation

⏱ 2mℹ️ Source: QB

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