Mathematics - Trigonometric Equation Question with Solution | TestHub

MathematicsTrigonometric EquationTrigonometric EquationHard2 minPYQ_2024

MathematicsHardnumerical

The number of solutions of $sin^{2} x + (2 + 2 x - x^{2}) sin x - 3 (x - 1)^{2} = 0$ , where $- π \leq x \leq π$ , is________

Answer:

2.00

Solution:

$sin^{2} x - (x^{2} - 2 x - 2) sin x - 3 (x - 1)^{2} = 0$
$sin x = - 3 (reject) or (x - 1)^{2} sin x = (x - 1)^{2}$

Stream:JEESubject:MathematicsTopic:Trigonometric EquationSubtopic:Trigonometric Equation

⏱ 2mℹ️ Source: PYQ_2024

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