Mathematics - Trigonometric Equation Question with Solution | TestHub

MathematicsTrigonometric EquationTrigonometric EquationEasy2 minPYQ_2019

MathematicsEasysingle choice

If $0 \leq x < \frac{π}{2},$ then the number of values of $x$ for which $\sin x - \sin 2 x + \sin 3 x = 0,$ is:

Answer:

Solution:

$\sin x - \sin 2 x + \sin 3 x = 0$

$\Rightarrow \sin x + \sin 3 x - \sin 2 x = 0$

$\Rightarrow 2 \sin 2 x . \cos x - \sin 2 x = 0$

$\Rightarrow \sin 2 x = 0$ or $\cos x = \frac{1}{2}$

$\Rightarrow 2 x = 0$ or $x = \frac{π}{3}$

$\Rightarrow x = 0$ or $x = \frac{π}{3}$

$∴$ Number of solutions $= 2$

Stream:JEESubject:MathematicsTopic:Trigonometric EquationSubtopic:Trigonometric Equation

⏱ 2mℹ️ Source: PYQ_2019

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