The solution of ( 2 cos x − 1 ) ( 3 + 2 cos x ) = 0 in the interval 0 ≤ x ≤ 2 π is

We have ( 2 cos x − 1 ) ( 3 + 2 cos x ) = 0 If 2 cos x − 1 = 0 , then cos x = 2 1 ∴ x = π /3 , 5 π /3 If 3 + 2 cos x = 0 , the cos x = − 3/2 which is not possible.

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MathematicsTrigonometric EquationTrigonometric EquationMedium2 minPYQ_2014

MathematicsMediumsingle choice

The solution of $(2 cos x - 1) (3 + 2 cos x) = 0$ in the interval $0 \leq x \leq 2 π$ is

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We have $(2 cos x - 1) (3 + 2 cos x) = 0$ If $2 cos x - 1 = 0,$ then $cos x = \frac{1}{2}$ $∴ x = π /3, 5 π /3$ If $3 + 2 cos x = 0,$ the $cos x = - 3/2$ which is not possible.

Stream:BITSATSubject:MathematicsTopic:Trigonometric EquationSubtopic:Trigonometric Equation

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