If f ( x ) = 1 + x 2 x , then (fof of ) ( x ) is

f ( x ) = 1 + x 2 x ( f o f ) ( x ) = 1 + 1 + x 2 x 2 1 + x 2 x = 2 x 2 + 1 x ( f o f o f ) ( x ) = 1 + 2 x 2 + 1 x 2 2 x 2 + 1 x = 1 + 3 x 2 x

Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsDomain-RangeHard2 minPYQ_2010

MathematicsHardsingle choice

If $f (x) = \frac{x}{1 + x ^{2}}$ , then (fof of $) (x)$ is

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Solution:

$f (x) = \frac{x}{1 + x ^{2}}$ $(f o f) (x) = \frac{\frac{x}{1 + x ^{2}}}{1 + \frac{x ^{2}}{1 + x ^{2}}} = \frac{x}{2 x ^{2} + 1}$ $(f o f o f) (x) = \frac{\frac{x}{2 x ^{2} + 1}}{1 + \frac{x ^{2}}{2 x ^{2} + 1}} = \frac{x}{1 + 3 x ^{2}}$

Stream:BITSATSubject:MathematicsTopic:FunctionsSubtopic:Domain-Range

⏱ 2mℹ️ Source: PYQ_2010

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