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Mathematics - Trigonometric Equation Question with Solution | TestHub

MathematicsTrigonometric EquationTrigonometric EquationEasy2 minPYQ_2007

MathematicsEasysingle choice

The number of solutions of the pair of equations $2 sin^{2} θ - cos 2 θ = 0$ and $2 cos^{2} θ - 3 sin θ = 0$ in the interval $[0, 2 π]$ is

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Solution:

$2 sin^{2} θ - cos 2 θ = 0 \Rightarrow sin^{2} θ = \frac{1}{4}$ Also, $2 cos^{2} θ = 3 sin θ \Rightarrow sin θ = \frac{1}{2}$ $\Rightarrow$ Two solutions in $[0, 2 π]$ .

Stream:JEE_ADVSubject:MathematicsTopic:Trigonometric EquationSubtopic:Trigonometric Equation

⏱ 2mℹ️ Source: PYQ_2007

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