Mathematics - Trigonometric Equation Question with Solution | TestHub

MathematicsTrigonometric EquationTrigonometric EquationMedium2 minPYQ_2006

MathematicsMediumsingle choice

The number of values of $x$ in the interval $[0, 3 π]$ satisfying the equation $2 sin^{2} x + 5 sin x - 3 = 0$ is

Answer:

Solution:

$2 sin^{2} x + 5 sin x - 3 = 0$ $\Rightarrow (sin x + 3) (2 sin x - 1) = 0$ $\Rightarrow sin x = \frac{1}{2} ∴ ln (0, 3 π), x$ has 4 values

Stream:JEESubject:MathematicsTopic:Trigonometric EquationSubtopic:Trigonometric Equation

⏱ 2mℹ️ Source: PYQ_2006

Loading discussions...