In a △ A BC , the coordinates of B are ( 0 , 0 ) , AB = 2 , ∠ A BC = 3 π and the mid point of BC is ( 2 , 0 ) . The centroid of triangle is

Let A ( h , k ) then cos 6 0 ∘ = 2 h ⇒ h = 1 ; sin 6 0 ∘ = 2 k ⇒ k = 3 . ∴ A ( 1 , 3 ) . ∴ centroid = ( 3 5 , 3 3 ) .

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Mathematics - Straight Lines Question with Solution | TestHub

MathematicsStraight LinesPosition of a pointMedium2 minQB

MathematicsMediumsingle choice

In a $△ A BC$ , the coordinates of B are $(0, 0), AB = 2, ∠ A BC = \frac{π}{3}$ and the mid point of BC is $(2, 0)$ . The centroid of triangle is

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Let $A (h, k)$ then $cos 6 0^{\circ} = \frac{h}{2} \Rightarrow h = 1; sin 6 0^{\circ} = \frac{k}{2} \Rightarrow k = 3 . ∴ A (1, 3) . ∴$ centroid $= (\frac{5}{3}, \frac{3}{3})$ .

Stream:JEESubject:MathematicsTopic:Straight LinesSubtopic:Position of a point

⏱ 2mℹ️ Source: QB

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