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Mathematics - Straight Lines Question with Solution | TestHub

MathematicsStraight LinesPair of St. linesMedium2 minQB

MathematicsMediummultiple choice

The equation of the diagonal of the square formed by the pairs of lines $x y + 4 x - 3 y - 12 = 0$ and $x y - 3 x + 4 y - 12 = 0$ is

Options:(select one or more)

Answer:

A, B

Solution:

$(x - 3) (y + 4) = 0, (x + 4) (y - 3) = 0$ . The vertices are $A = (- 4, - 4), B = (3, - 4), C = (3, 3)$ , $D = (- 4, 3)$ . Diagonal AC is $x = y$ ; Diagonal BD is $x + y + 1 = 0$ .

Stream:JEESubject:MathematicsTopic:Straight LinesSubtopic:Pair of St. lines

⏱ 2mℹ️ Source: QB

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