Mathematics - Straight Lines Question with Solution | TestHub

MathematicsStraight LinesAngle bisectorsMedium2 minQB

MathematicsMediumsingle choice

Find the angle bisector of $x + y - 1 = 0$ and $7 x + y - 3 = 0$ that contains the origin.

Answer:

Solution:

Equating normalized expressions gives $(x + y - 1) / 2 = (7 x + y - 3) / (52)$ , hence $x - 2 y + 1 = 0$ .

Stream:JEESubject:MathematicsTopic:Straight LinesSubtopic:Angle bisectors

⏱ 2mℹ️ Source: QB

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