Mathematics - Straight Lines Question with Solution | TestHub

$\Rightarrow A_1$ is image of $A$ $\mathrm{y}=-2\mathrm{x}$ ${\mathrm{A}}_1=\left(-\frac{11}{5},\frac{2}{5}\right)$ $\Rightarrow A_2$ is image of $A$ in $y=x$ ${\mathrm{A}}_2=(2,1)$ ⇒ equation of $BC$ is $x-7y+5=0$ ⇒ Incenter $\equiv (0,0)$ $\therefore r=\left|\frac{5}{\sqrt{1+49}}\right|=\left|\frac{5}{5\sqrt{2}}\right|=\frac{1}{\sqrt{2}}$