If the area of the rhombus enclosed by the lines l x ± m y ± n = 0 be 2square units, then

By solving the sides of the rhombus, the vertices are ( 0 , m − n ) , ( l − n , 0 ) ( 0 , m n ) , ( l n , 0 ) ∴ The area = 2 1 ( m 2 n ) ( l 2 n ) = 2 ⇒ n 2 = l m

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Mathematics - Straight Lines Question with Solution | TestHub

MathematicsStraight LinesIntersection of linesMedium2 min

MathematicsMediumsingle choice

If the area of the rhombus enclosed by the lines $l x \pm m y \pm n = 0$ be 2square units, then

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Answer:

Solution:

By solving the sides of the rhombus, the vertices are

$(0, \frac{- n}{m}), (\frac{- n}{l}, 0) (0, \frac{n}{m}), (\frac{n}{l}, 0)$

∴ The area $= \frac{1}{2} (\frac{2 n}{m}) (\frac{2 n}{l}) = 2 \Rightarrow n^{2} = l m$

Stream:JEESubject:MathematicsTopic:Straight LinesSubtopic:Intersection of lines

⏱ 2m

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