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MathematicsStatisticsMedianMedium2 minPYQ_2024
MathematicsMediumsingle choice

Let M denote the median of the following frequency distribution.

 Class 0-44-88-1212-1616-20 Frequency 391086

Then 20M is equal to :

Options:

Answer:
D
Solution:

M=l+N2-Cfh

Here, N=3+9+10+8+6=36

N2=18

So, median class is 8-12

l=8, C=22, f=10, h=4

M=8+18-1210×4

M=10.4

20 M =208

Stream:JEESubject:MathematicsTopic:StatisticsSubtopic:Median
2mℹ️ Source: PYQ_2024

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