Let α , β ∈ R . Let the mean and the variance of 6 observations − 3 , 4 , 7 , − 6 , α , β be 2 and 23 , respectively. The mean deviation about the mean of these 6 observations is :

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​ 6 ∑ x i ​ ​ = 2 and N ∑ x i 2 ​ ​ − μ 2 = 23 α + β = 10 α 2 + β 2 = 52 ​ solving we get α = 4 , β = 6 6 ∑ ∣ x i ​ − x ˉ ∣ ​ = 6 5 + 2 + 5 + 8 + 2 + 4 ​ = 3 13 ​

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