Mathematics - Statistics Question with Solution | TestHub

We know${\sigma }^2\le \frac{1}{4}{\left(M-m\right)}^2$.

Where $M$ is upper bound of value of any random variable and $m$ is lower bound of any random variable,

$\Rightarrow {\sigma }^2\le \frac{1}{4}{\left(10-0\right)}^2$

$\Rightarrow {\sigma }^2<25$, (removed equality sign because $m>0$)

$\Rightarrow -5<\sigma <5$

From given options $\sigma \ne 6$.