Mathematics - Sets and Relations Question with Solution | TestHub

From the given condition, $\mathrm{a}+\mathrm{c}=62\mathrm{k};\mathrm{b}+\mathrm{c}=42\mathrm{k}$ and $\mathrm{c}=20\mathrm{k}$ Hence $\mathrm{a}=42\mathrm{k}$ and $\mathrm{b}=22\mathrm{k}$ Number of students who failed in none means passed in both $=\mathrm{n}=100\mathrm{k}-(\mathrm{a}+\mathrm{b}+\mathrm{c})$ $=100\mathrm{k}-(42\mathrm{k}+22\mathrm{k}+20\mathrm{k})=16\mathrm{k}$. or $16\%$