Mathematics - Sets and Relations Question with Solution | TestHub

Since, $(b, c)\in R_1$ but $(c, b)\notin R_1$

Hence, $R_1$ is not symmetric.

In $R_1 : \left(b, c\right)\in R_1$ and $\left(c, a\right)\in R_1$ but $\left(b, a\right)\notin R_1$

So, $R_1$ is not transitive.

$R_2$ is symmetric.

In $R_2 : \left(b, a\right)\in R_2$ and $\left(a, c\right)\in R_1$ but $\left(b, c\right)\notin R_2$

So, $R_2$ is not transitive.