Mathematics - Sets and Relations Question with Solution | TestHub

$N_1+N_2+N_3+N_4+N_5=$ Total ways – {when no odd}

Total ways ${=}^9{C}_5$

Number of ways when no odd, is zero     ($\because$ only available even are $2, 4, 6, 8$)

$\therefore { }^9{C}_5-\mathrm{zero}=126$