Let A = { x : x ∈ R , ∣ x ∣ < 1 } ; B = { x : x ∈ R , ∣ x − 1∣ ≥ 1 } and A ∪ B = R − D , then the set D is

A = [ x : x ∈ R , − 1 < x < 1 ] B = [ x : x ∈ R : x − 1 ≤ − 1 or x − 1 ≥ 1 ] = [ x : x ∈ R : x ≤ 0 or x ≥ 2 ] ∴ A ∪ B = R − D , where D = [ x : x ∈ R , 1 ≤ x < 2 ]

Mathematics - Sets and Relations Question with Solution | TestHub

MathematicsSets and RelationsQuestions on number of relations and setsMedium2 minPYQ_2010

MathematicsMediumsingle choice

Let $A = {x : x \in R, ∣ x ∣ < 1}$ ; $B = {x : x \in R, ∣ x - 1∣ \geq 1} and A \cup B = R - D,$ then the set $D$ is

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$A = [x : x \in R, - 1 < x < 1] B = [x : x \in R : x - 1 \leq - 1 or x - 1 \geq 1] = [x : x \in R : x \leq 0 or x \geq 2] ∴ A \cup B = R - D,$ where $D = [x : x \in R, 1 \leq x < 2]$

Stream:BITSATSubject:MathematicsTopic:Sets and RelationsSubtopic:Questions on number of relations and sets

⏱ 2mℹ️ Source: PYQ_2010

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