Evaluate ∑ k = 1 n ( k 2 + 1 ) k ! .

Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesSpecial sequences/seriesMedium2 minQB

MathematicsMediumsingle choice

Evaluate $\sum_{k = 1}^{n} (k^{2} + 1) k!$ .

Answer:

Solution:

$(k^{2} + 1) k! = k (k + 1)! - (k - 1) k!$ . The sum telescopes to $n (n + 1)!$ .

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:Special sequences/series

⏱ 2mℹ️ Source: QB

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