Let A = ∑ i = 1 10 ∑ j = 1 10 min { i , j } and B = ∑ i = 1 10 ∑ j = 1 10 max { i , j } . Find A + B .

Since min { i , j } + max { i , j } = i + j , A + B = ∑ i , j ( i + j ) = 20 ∑ i = 1 10 i = 20 ⋅ 55 = 1100 .

Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesSpecial sequences/seriesMedium2 minQB

MathematicsMediuminteger

Let $A = \sum_{i = 1}^{10} \sum_{j = 1}^{10} min {i, j}$ and $B = \sum_{i = 1}^{10} \sum_{j = 1}^{10} max {i, j}$ . Find $A + B$ .

Answer:

1100

Solution:

Since $min {i, j} + max {i, j} = i + j, A + B = \sum_{i, j} (i + j) = 20 \sum_{i = 1}^{10} i = 20 \cdot 55 = 1100$ .

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:Special sequences/series

⏱ 2mℹ️ Source: QB

Loading discussions...