Mathematics - Sequence & Series Question with Solution | TestHub

Use ${\sum }_{k=1}^{n}k=\frac{n(n+1)}{2},{\sum }_{k=1}^n{k}^2=\frac{n(n+1)(2n+1)}{6}$ and ${\sum }_{k=1}^n{k}^3={\left[\frac{n(n+1)}{2}\right]}^2$. Find the sum of 16 terms: $1^3/1+$ $\left(1^3+2^3\right)/(1+3)+\left(1^3+2^3+3^3\right)/(1+3+5)+\cdots$.