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Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesH.P.Medium2 minQB

MathematicsMediumsingle choice

If $a, b, c$ are in H.P. and the fractions exist, find $1/ (b - a) + 1/ (b - c)$ .

Options:

Answer:

Solution:

From $2/ b = 1/ a + 1/ c$ , we get $b = 2 a c / (a + c)$ . Then $b - a = a (c - a) / (a + c)$ and $b - c = c (a - c) / (a + c)$ . Their reciprocals sum to $(a + c) / (a c) = 2/ b$ .

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:H.P.

⏱ 2mℹ️ Source: QB

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