A three-digit number has digits in G.P. The sum of the outer digits exceeds twic | TestHub

MathematicsMediumnumerical

Passage / Comprehension

A three-digit number has digits in G.P. The sum of the outer digits exceeds twice the middle digit by 1 , and the sum of the left and middle digits is two-thirds of the sum of the middle and right digits. Find the number.

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Answer:

469.00

Solution:

Let the digits be $a, a r, a r^{2}$ . Then $a (r - 1)^{2} = 1$ , while $a + a r = \frac{2}{3} (a r + a r^{2})$ gives $2 r^{2} - r - 3 = 0$ . The admissible digit solution is $r = 3/2, a = 4$ , yielding digits 4, 6, 9 and number 469.

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:G.P.

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Mathematics - Sequence & Series Question with Solution | TestHub

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