Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesA.P.Easy2 minPYQ_2019

MathematicsEasystatement

If 19 th term of a non-zero A.P. is zero, then its (49th term): (29th term) is:

Options:

Answer:

Solution:

Let first term and common difference of $A P$ be a and d respectively, then $t_{n} = a + (n - 1) d$ $∴ t_{19} = a + 18 d = 0$ $∴ a = - 18 d$ $∴ \frac{t _{49}}{t _{29}} = \frac{a + 48 d}{a + 28 d}$ $= \frac{- 18 d + 48 d}{- 18 d + 28 d} = \frac{30 d}{10 d} = 3$ $t_{49} : t_{29} = 3 : 1$

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:A.P.

⏱ 2mℹ️ Source: PYQ_2019

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