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MathematicsSequence & SeriesA.P.Medium2 minPYQ_2018
MathematicsMediumnumerical

LetXbe the set consisting of the first2018terms of the arithmetic progression1,6,11, ,andYbe the set consisting of the first2018terms of the arithmetic progression9,16,23, . Then, the number of elements in the setXYis___.

Answer:
3748.00
Solution:

X:1, 6, 11, ,10086
Y:9, 16, 23,.,14128
XY:16, 51, 86,..
Letm=nXY
  16+m-1×3510086
  m288.71
  m=288
  nXY=nX+nY-nXY
=  2018+2018-288=3748

Stream:JEE_ADVSubject:MathematicsTopic:Sequence & SeriesSubtopic:A.P.
2mℹ️ Source: PYQ_2018

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