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MathematicsSequence & SeriesA.P.Medium2 minPYQ_2018
MathematicsMediumstatement

Ifx1, x2, .., xnand1h1, 1h2, .., 1hnare two A.P.s such thatx3=h2=8 & x8=h7=20, thenx5·h10is equal to

Options:

Answer:
D
Solution:

Let d1 be the common difference of the A.P. x1,x2,, then x8-x3=5 d1=12

x5=x3+2 d1=8+2×125=12.8

Let d2 be the common difference of the other sequence then

5 d2=120-18=-340d2

1 h10=1 h7+3 d2=1200h10=200

x5·h10=12.8×200=2560

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:A.P.
2mℹ️ Source: PYQ_2018

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